A Low Noise Sub-Sampling PLL in Which Divider Noise is Eliminated and PD/CP Noise is Not Multiplied by $N ^{2}$
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Citations
Cryo-CMOS Circuits and Systems for Quantum Computing Applications
Analog-to-Digital Conversion
Spur Reduction Techniques for Phase-Locked Loops Exploiting A Sub-Sampling Phase Detector
A 9.2–12.7 GHz Wideband Fractional-N Subsampling PLL in 28 nm CMOS With 280 fs RMS Jitter
A 79-GHz 2 $\times $ 2 MIMO PMCW Radar SoC in 28-nm CMOS
References
A filtering technique to lower LC oscillator phase noise
Charge-Pump Phase-Lock Loops
Concepts and methods in optimization of integrated LC VCOs
A Low-Noise Wide-BW 3.6-GHz Digital $\Delta\Sigma$ Fractional-N Frequency Synthesizer With a Noise-Shaping Time-to-Digital Converter and Quantization Noise Cancellation
A Low-Noise, Wide-BW 3.6GHz Digital ΔΣ Fractional-N Frequency Synthesizer with a Noise-Shaping Time-to-Digital Converter and Quantization Noise Cancellation
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Frequently Asked Questions (21)
Q2. How much rms jitter does the FLL output have?
Integrating the phase noise spectrum from 10 kHz to 40 MHz yields a total phase noise of 56.8 dBc, which translates to an rms jitter of 0.15 ps at the 2.21 GHz output frequency.
Q3. What is the CP noise contribution in a PLL?
Inside the PLL bandwidth, and the PLL in-band phase noise contributed by the CP can be approximated as(2)where the phase noise is expressed with the often used single sideband noise power to carrier power ratio and is the power spectral density of the CP current noise.
Q4. How can the noise contribution of the SSPD be calculated?
The noise contribution of the SSPD can be calculated by relating the voltage noise at the SSPD output and the corresponding VCO phase error in steady state:(12)where is the sampling capacitor value.
Q5. What is the main source of the noise in the SSPLL?
the authors observed that the SSPLL has such a low PD/CP noise (and no divider noise) that the Ref buffer becomes the dominant source of the in-band phase noise as well as the dominant source of the power consumption.
Q6. What are the drawbacks of a sub-sampling PLL?
Despite of the low noise feature, a sub-sampling PLL has drawbacks like difficulty of integration (large filter capacitor needed due to high detection gain) and limited frequency acquisition range.
Q7. What is the amplitude of the signal coming from the crystal oscillator?
The crystal oscillator output passes an off-chip attenuator before it is fed into the chip; such that the signal arriving on-chip has 1.8 - amplitude fitting to the 1.8 V supply.
Q8. Why does the SSPD have a limited frequency acquisition range?
Due to its sinusoidal characteristic, the SSPD has limited frequency acquisition range similar to the case of the mixer based PD.
Q9. What is the common implementation of the loop filter?
In a charge pump PLL, the most common implementation of the loop filter is a passive RC filter where a resistor is in series with a capacitor .
Q10. What is the effect of switching on the current sources only for a fraction of time?
On the other hand, switching on the current sources only for a fraction of time also reduces CP noise:(19)Since the reduction of the CP noise suppression factor is stronger than the reduction of the CP noise, the overall effect is that the in-band phase noise due to CP increases with :(20)By a careful choice of , the value of will not be “unnecessarily high” but still high enough to keep the CP a negligible source of the loop noise.
Q11. What is the CP feedback gain of the SSPLL?
In the steady state, the VCO phase error is small and the CP feedback gain of the SSPLL can be calculated as(5)The authors see that there is no in (5), which means that is not related to .
Q12. What is the noise model parameter of the MOS transistor?
Assuming that the noise of the CP UP/DN current source is dominated by a single MOS transistor with transconductance , the power spectral density of the (thermal) noise generated by the CP can be estimated as [10]:(4)where is a noise model parameter of the MOS transistor typically in the range of 2/3 to 1.5.
Q13. What is the disadvantage of a sub-sampling PLL?
In order to overcome these drawbacks, pulsewidth gain control is added to the sub-sampling PD/CP to reduce the detection gain and thus the needed filter capacitor value.
Q14. What is the noise of the rms output?
The measured in-band phase noise is 126 dBc/Hz at 200 kHz offset and the rms output jitter integrated from 10 kHz to 40 MHz is 0.15 ps.
Q15. What is the effect of having a larger CP noise on the loop?
when the CP noise becomes negligible and other loop components’ noise start dominating the loop noise, having a further largerstill reduces the CP noise but will hardly reduce the overall loop noise as shown in Fig. 7(b).
Q16. What is the reason to use a PD?
Note that this PD works without using a divider as soon as the ratio is an integer, which is an often mentioned reason to use it.
Q17. What is the phase domain model for noise analysis?
Using this phase domain model for noise analysis, the authors see that the reference clock phase noise is still multiplied by when transferred to the output, same as in a classical PLL.
Q18. How can the authors calculate the CP noise contribution in a PLL?
Using the phase domain model in Fig. 1(b), the close loop CP noise transfer function can be calculated as(1)where is the PLL open loop transfer function.
Q19. What is the CP feedback gain of the classical three-state PFD/CP?
The CP feedback gain of the classical three-state PFD/CP can be calculated as(3)where is the bias current of the CP current sources, is the mean CP output current, and are respectively the VCO and divider phase error.
Q20. What is the CP noise contribution in a feedback system?
In order to calculate the CP noise contribution in a feedback system like a PLL, it is convenient to define a CP feedback gain as the gain from the PLL output to the CP output current.
Q21. What is the advantage of the sampling PD?
Although the sampling PD has been existing for years, its potential of achieving very low in-band phase noise is not fully appreciated to the best of their knowledge.