An optimal wheel-torque control on a compliant modular robot for wheel-slip minimization
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...The slip reduction algorithms estimate dynamics of UGV platforms at the current moment and calculate the appropriate torque of motors so that the slip is minimized (Xu et al., 2016; Kobayashi et al., 2018; Siravuru et al., 2017)....
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"An optimal wheel-torque control on ..." refers background or methods in this paper
...Wheel-torque optimization is carried out using the three objective functions as given in Eqs (11)– (13) at all the set points between 0 and hmax ....
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...(11)) performs consistently well on all the metrics....
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...Therefore, for phase-1, the equality constraints are obtained from Eqs....
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...Optimization Results and Discussion Wheel-torque optimization is carried out using the three objective functions as given in Eqs (11)– (13) at all the set points between 0 and hmax ....
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...(1)–(5) and for phase-2, it is obtained from Eqs....
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"An optimal wheel-torque control on ..." refers background in this paper
...(1)–(5) are obtained by eliminating the constraint forces (f xli , fyli ,f xwi and fywi) from the above equations....
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...∑ Fx = 0 N1 − F2 − F3 − F4 = 0 (1) ∑ Fy = 0 3wl + 4ww − F1 − N2 − N3 − N4 = 0 (2) ∑ MJ1 = 0 F1(lcosφ1 + r) + N1lsinφ1 − wl[(l/2)cosφ1-csinφ1] − k1φ1 − wwlcosφ1 = 0 (3) ∑ MJ2 = 0 F2r + N2l − wwl − wl(l/2) − [wl + ww − F1](l + l0) − k2φ2 + k1φ1 = 0 (4)...
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...(1) is obtained by substituting the values f xl2, f xw3 and f xw4 from the above into Eq....
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...(1)–(5) and for phase-2, it is obtained from Eqs....
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...Equations (1)–(5) and (6)–(10) contain the minimal set of static-equilibrium equations for the first and second phases of climbing of the robot as shown in Figs....
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"An optimal wheel-torque control on ..." refers background in this paper
...(1)–(5) are obtained by eliminating the constraint forces (f xli , fyli ,f xwi and fywi) from the above equations....
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...∑ MW4 = 0 F3r + N3l − wwl − wl(l/2) − [2(wl + ww) − F1 − N2](l + l0) + k2φ2 + F4r = 0 (5) ∑ Fx = 0 N1 − F3 − F4 = 0 (6) ∑ Fy = 0 3wl + 4ww − F1 − N3 − N4 = 0 (7) ∑ MJ1 = 0 F1(lcos(φ1 + φ2) + r) + N1lsin(φ1 + φ2) − wl[(l/2)cos(φ1 + φ2) − csin(φ1 + φ2)] − k1φ1 − wwlcos(φ1 + φ2) = 0 (8) ∑ MJ2 = 0 [F1 − (wl + ww)](l + l0)cosφ2 − wl(l/2cosφ2 − csinφ2) − wwlcosφ2 + k1φ1 − k2φ2 + N1(l + l0)sinφ2 = 0 (9) ∑ MW4 = 0 F3r + N3l − wwl − wl(l/2) − [2wl + 2ww − F1](l + l0) + k2φ2 + F4r = 0....
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...(v) Equation (5) is obtained by substituting values of fyl2, fyw3, τw3 and τw4 from item − ii above, Eqs....
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...(1)–(5) and for phase-2, it is obtained from Eqs....
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...Equations (1)–(5) and (6)–(10) contain the minimal set of static-equilibrium equations for the first and second phases of climbing of the robot as shown in Figs....
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