Global solution and smoothing effect for a non-local regularization of a hyperbolic equation
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Citations
Calcul des Probabilités. By Paul Lévy. Pp. 350. Fr. 40. 1925. (Gauthier-Villars.)
Fractal first-order partial differential equations
The Hybrid High-Order Method for Polytopal Meshes: Design, Analysis, and Applications
Occurrence and non-appearance of shocks in fractal burgers equations
Entropy formulation for fractal conservation laws.
References
First order quasilinear equations in several independent variables
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Frequently Asked Questions (9)
Q2. What is the proof of the uniqueness result?
T0 > 0 only depending on R such that, if T1 ≤ T0, the authors have k(T1, R) < 1; for T1 ≤ T0, there exists therefore at most one solution to (1.1) on ]0, T1[ bounded by R.Step 2: proof of the uniqueness result.
Q3. What is the equicontinuity of u on [0,[?
Since p is even, by definition of uδ on ]pδ, (p+1)δ] and (2.5), the authors have uδ((p+1)δ) = K(2((p + 1)δ − t)) ∗ (K(2(t − pδ)) ∗ uδ(pδ)) = K(2((p + 1)δ − t)) ∗ uδ(t).
Q4. What is the equicontinuity of u in C?
Thanks to (6.1), the authors see that the lipschitz constant of uδ on [(2n+ 1)δ, 2(n + 1)δ] does not depend on δ or n ≥ 0: there exists C0 such that, for all δ ∈]0, δ0], for all n ≥ 0 and all (t, s) ∈ [(2n+ 1)δ, 2(n+ 1)δ],||uδ(t)− uδ(s)||L1(R) ≤ C0|t− s|. (6.3)Taking into account that uδ(s, ·) ∈ W 1,1(R) and the estimates of (6.1), some classical cuttings of integrals involving approximate units give, for all δ ∈]0, δ0], all t > 0, all s ≥ 0 and all η > 0,||K(t) ∗ uδ(s)− uδ(s)||L1(R) ≤ 2||u0||L1(R) ∫ |y|≥η K(t, y) dy + η||u′0||L1(R). (6.4)Let us now prove the equicontinuity of {uδ , δ ∈]0, δ0]} in C([0,∞[;L1(R)).
Q5. What is the proof of the lemma?
Since (F(fn))n≥1 is bounded by 1 (the L1-norm of fn for all n ≥ 1), this convergence is also true in S ′(R) and, taking the inverse Fourier transform, the authors see that fn → F−1(e−c|·| λ) = K(c, ·) in S ′(R) as n → ∞. fn being nonnegative for all n, the authors deduce that K is nonnegative on {c} × R; the homogeneity property (2.1) below concludes then the proof of the lemma.
Q6. What is the reasoning of Step 2 in the proof of Proposition 5.1?
The reasoning of Step 2 in theproof of Proposition 5.1 (with ∂nx (f(u))(t0 + ·, ·) instead of F (·, ·, v(·, ·))) allows to compute the spatial derivative of the last term in (5.12) by derivation under the integral sign, and, thanks to (5.13), proves item ii) for ∂n+1x u.Property (5.11) for the derivative of order n+1 simply comes from the derivation of this formula at rank n, and the induction is complete.
Q7. What is the equicontinuity of u in L1(Q)?
Let p ≤ q be integers such that pδ ≤ t < (p + 1)δ and qδ ≤ s < (q + 1)δ; because of the different behaviours of uδ (see (6.2)), the authors must separate the cases depending on the parity of p and q; since all these cases are similar, the authors study only one, for example p even and q odd.
Q8. what is the idea of the proof of Proposition 3.1?
The estimate (2.2) allows to see, as in Step 1 of the proof of Proposition 3.1, that, by derivation and continuity under the integral sign, K(t, ·)∗v0 is derivable on R and that (t, x) ∈]0, T [×R → ∂x(K(t, ·) ∗ v0)(x) = ∂xK(t, ·) ∗ v0(x) is continuous.
Q9. What is the idea of the proof of Proposition 3.1?
|∞||v||ET s1/λ(t− s)1/λ . (5.3)This last function is integrable with respect to s ∈]0, t[, and the authors can thus apply the theorem of derivation under the integral sign to see that∂xH(t, x) = ∫ t0∂xK(t− s, ·) ∗ (∂xF (s, ·, v(s, ·)) + ∂ζF (s, ·, v(s, ·))∂xv(s, ·))(x) ds.(5.4)If ∂xv was bounded, the continuity of ∂xH would be a consequence of Proposition 3.1.