Q2. How did the model reproduce the intensity profiles of CNTs?
The model reproduced experimental intensity profiles well when a combination of a Gaussian and a Lorentzian function for the probe shape was used.
Q3. How much voltage was used to acquire all images in this study?
An acceleration voltage of 12 kV was found to be a good tradeoff between resolution and signal-to-noise ratio and was used when acquiring all images in this study.
Q4. What was used as a parameter when simulating intensity profiles?
The inner and outer diameter of the CNTs obtained from the TEM images was used as parameters when simulating intensity profiles, Isim.
Q5. How many CNTs were used in this study?
Since all CNTs used in this study had d > 1 nm, the diameters measured in the TEM should deviate less than 10% from the true diameter.
Q6. What was the integration in Eq. 8?
The integration in Eq. 8 was performed numerically in MATLAB, were both isim(r− r′) and δsim(r′) were divided into small elements.
Q7. What was the solution containing the CNTs?
The solution containing the CNTs was drop-casted onto a holey carbon support film for TEM (R 2/1 produced by Quantifoil) and then allowed to dry.
Q8. What is the way to deconvolute a full SEM image?
Knowing the exact probe shape, one can deconvolute a full SEM image to obtain the SE yield, and in turn from that retrieve the intrinsic nanotube dimensions.
Q9. What is the probability of escaping a specimen?
The probability of escaping a specimen decreases exponentially with the distance travelled in the solid, z:Pescape ∝ e−αz (4)with α being the absorption coefficient for SE of the specimen material.
Q10. What is the simplest way to deconvolute a SEM image?
The authors have used the two dimensional version of Eq. 9 as the input point spread function in the MATLAB-function deconvblind to deconvolute SEM images.