Onset of Convection in a Triangular Porous Prism with Robin-Type Thermal Wall Condition
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Citations
Application of a Robin boundary condition to surface waves
References
Convection of a fluid in a porous medium
Convection Currents in a Porous Medium
Onset of Thermohaline Convection in a Porous Medium
Convection in a box of porous material saturated with fluid
The stability of a viscous liquid in a vertical tube containing porous material
Related Papers (5)
Numerical Analysis of Natural Convection in a Cylindrical Envelope with an Internal Concentric Cylinder with Slots
Frequently Asked Questions (14)
Q2. What are the future works in "Onset of convection in a triangular porous prism with robin-type thermal wall condition" ?
It proved useful to apply a thermal Robin condition for utilizing the benchmarking possibilities of an analytical solution for the 2D Helmholtz equation that constitutes normal modes.
Q3. What is the kinematic condition of the cylinder walls?
As kinematic condition the authors take the simple condition of impermeable wallsn · v = 0, at the cylinder contour, (28)where n is the horizontal unit normal vector on the cylinder surface, pointing out from the porous cylinder.
Q4. What is the basic solution of eqs. (9)-(11)?
In their stability analysis the authors disturb the basic state (15) with perturbed fieldsv = vb + v, T = Tb(z) +Θ, P = Pb(z) + p ′. (16)where the perturbations v, Θ, p′ are functions of x, y, z and t. Linearizing eqs. (9)-(11) with respect to perturbations and eliminating the pressure gives∇2w = R∇21Θ, (17)∂Θ∂t − w = ∇2Θ.
Q5. What is the preferred mode for all aspects ratios?
Haugen and Tyvand [8] found that the axisymmetric mode is preferred for all aspects ratios when the cylinder cross-section is circular.
Q6. What is the general trend of the Rayleigh number?
A general trend is that the Rayleigh number always decreases with increasing a, which is plausible since increasing a represents an enhanced loss of heat by conduction through the impermeable cylinder walls.
Q7. What is the analogy solution for a 4th order eigenvalue problem?
The analogy solution (35) is a degenerate solution for a 4th order eigenvalue problem, in contrast to their numerical non-normal mode solution for an irreducible 4th order problem.
Q8. What is the thermal Robin condition for the cylinder wall?
The authors will allow a thermal Robin condition for the cylinder wall, whereby the standard case of impermeable adiabatic walls (Wooding [3]) arises as a limit case.
Q9. What are the dimensions of the triangle in the x, y plane?
The corners of the triangle in the x, y plane are termed O, A and B, with dimensionless coordinates (0, 0) (the origin), (L, 0) and (0, L), respectively.
Q10. What is the preferred length scale of the classical HRL problem?
the authors concentrate on the intermediate case L = 1 because it represents the preferred length scale of the classical HRL problem and highlights the differences between normal modes and non-normal modes.
Q11. What is the eigenvalue problem for the triangle?
The ordinary differential equation in the radial direction is solvable analytically for circular geometry, while no analytical methods are known for the same eigenvalue problem for the triangle.
Q12. What is the only paper that treats the onset problem in a 3D porous medium?
There exists only a handful of papers that treat the onset problem in a 3D porous medium where the normal-mode type of spatial dependence is challenged.
Q13. What is the symmetric thermal eigenfunctions of Figure 3?
where the mode numbers m and n are positive integers with m 6= n. Figure 4 gives the symmetric thermal eigenfunctions that are the normal-mode analogies of the symmetric non-normal mode solutions of Figure 3.
Q14. What is the eigenvalue problem for the horizontal perturbation temperature field?
The authors will now formulate and solve the 2D eigenvalue problem for the horizontal perturbation temperature field θ(x, y) as it is coupled to the poloidal vector potential ψ(x, y).