Some new results on stochastic comparisons of coherent systems using signatures
Summary (1 min read)
1 Introduction
- Consider a coherent system consisting of n components with lifetimes X1, . . . ,Xn, which are assumed to be independent and identically distributed (i.i.d.) continuous random variables.
- (1.1) Because of the fundamental property of a systems signature p, namely, that the distribution of the system lifetime T, given i.i.d. components lifetimes with c.d.f.
- These ordering properties are distribution-free in the sense that they do not depend on the common distribution of the components.
- This problem has been pursued further by many other researchers.
- The main results of the paper are given in the next section.
2 Main Results
- Using the above lemma, the authors prove the following result.
- Now using this observation, the second inequality follows from the assumption that uΨ ′(u) Ψ(u) is decreasing and positive for u ∈ (0, v).
- Combining the results of the above theorem with the previous theorem, the authors obtain the following general results which show how the hazard rate, the reversed hazard rate and the likelihood ratio orders between X and Y and signature vectors p and q are preserved by the lifetimes of the corresponding coherent systems.
3 Some numerical examples
- The authors present some coherent systems that satisfy the conditions of Theorem 2.3.
- Below the authors check this condition for various cases of k and r. .
- That is, the condition in Theorem 2.3 (b) is satisfied by such a system.
- The graphs of the functions Δ1(u) and Δ2(u) are given in Figures 2 and 3, respectively.
- The authors now provide a counterexample to illustrate that the condition (iv) in Theorem 2.6 of Navarro et al. (2013) for establishing likelihood ratio ordering is not satisfied, but it satisfies the conditions of their main result on likelihood ratio ordering between systems.
4 Conclusions
- The authors consider the problem of stochastically comparing the lifetimes TX(p) and TY(q) of two coherent systems with signature vectors p and q of the same size and with iid component lifetimes distributed according to X and Y , respectively.
- The results established in this paper generalize some of the known results in the literature.
- The authors first consider the case when a coherent system operates under two different sets of independent and identically distributed component lifetimes.
- The authors find simple sufficient conditions on the distribution of the signature vector under which the two systems are stochastically ordered.
- It will be interesting to examine whether their conjectures are true.
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"Some new results on stochastic comp..." refers result in this paper
...This problem has also been studied by Navarro et al. (2013). However, as seen by examples in the next section, their results are different from results of this paper....
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387 citations
"Some new results on stochastic comp..." refers background in this paper
...For further references on this topic, see Samaniego (2007) and Navarro et al. (2010)....
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373 citations
"Some new results on stochastic comp..." refers background in this paper
...It follows from the coherent property of the system that the lifetime of the system TX corresponds to exactly one of the order statistics, Xi:n, i = 1, . . . , n. Samaniego (1985) introduced the concept of the “signature” of a system which depends on the design of the system....
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...For example, Samaniego (1985) proved that a coherent system with n i.i.d. IFR (increasing failure rate) components is IFR if and only if the function 1(x) is increasing in x ∈ (0, ∞)....
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268 citations
"Some new results on stochastic comp..." refers background or methods or result in this paper
...This representation was used by Kochar et al. (1999) to stochastically compare two systems, each with the same i.i.d. components....
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...As mentioned in Kochar et al. (1999) and also explained in Navarro et al. (2008), the above results continue to hold when the vector (X1, . . . , Xn) has an exchangeable distribution....
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...Kochar et al. (1999) proved that if random lifetimes X1, . . . , Xn are i.i.d., then p ≥∗ q =⇒ TX( p) ≥∗ TX(q), (2) where ∗ stands for lr, hr, rh, and st orders....
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...Therefore, a result similar to (4) does not hold, in general, for hazard rate ordering....
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...(Kochar et al. (1999)) Let p and q be the signature vectors of two coherent systems with the same number of components, and let TX( p) and TX(q) be their lifetimes, where the elements of the vector X are i.i.d....
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Frequently Asked Questions (9)
Q2. What have the authors stated for future works in "Some new results on stochastic comparisons of coherent systems using signatures" ?
The authors plan to pursue this problem in the near future.
Q3. What is the hazard rate of a coherent system?
Consider a coherent system of order 4 with lifetimeTX(p) = max(X1,min(X2,X3,X4))with signature vector p = (0, 12 , 1 4 , 1 4 ), where Xi, i = 1, . . . , 4 are independent exponential random variables with common hazard rate 0.7.
Q4. What is the order of random lifetimes?
Kochar et al. (1999) proved that if random lifetimes X1, . . . ,Xn are i.i.d., thenp ≥∗ q =⇒ TX(p) ≥∗ TX(q), (1.3)where ∗ order stands for lr, hr, rh and st orders.
Q5. what is the hazard rate function of tx?
(2.2)and the hazard rate function of TX(p) ishTX(p)(t) =∑n i=1 ipi (n i ) F i−1(t)F n−i+1(t)∑ni=1 pi ∑i−1 j=1 (n j ) F j(t)F n−j (t) hX(t)=∑n−1 i=0 (n− i)pi+1 ( n i ) F i(t)Fn−i (t)∑n−1i=0 (∑n j=i+1 pj ) (n i ) F i(t)F n−i (t) hX(t)= Ψ1( F (t)F (t)) hX(t) (2.3)whereΨ1(x) =∑n−1 i=0 (n− i) (n i ) pi+1xi∑n−1 i=0 (∑n j=i+1 pj ) (n i ) xi(2.4)The reverse hazard rate function of TX(p) ish̃TX(p)(t) =∑n i=1 ipi (n i ) F i(t)Fn−i (t)∑ni=1 (∑i j=1 pj ) ( n i ) F i(t)F n−i (t) h̃X(t)= Ψ2(x)( F (t)F (t)) h̃X(t), (2.5)whereΨ2(x) =∑n i=1 ipi (n i ) x1∑ni=1 (∑i j=1 pj ) (n i ) xi(t)(2.6)First the authors prove the following lemma which gives simple sufficient conditions for the functionsΨ1 and Ψ2 to be monotone.
Q6. What is the likelihood ratio order of a coherent system?
Consider a coherent system of order 4 with signature vector p = (0, 23 , 1 3 , 0) , and lifetime T = max(min(X1,X2),min(X3,X4)), where X1,X2,X3,X4 are independent and identically distributed.
Q7. What is the hazard rate function of X1?
In Figure 1 the authors plot the hazard rate functions of TX(p) and TY (p) and it can be seen that the hazard rate functions cross at t = 5.5 even though X1 ≥hr Y1.
Q8. what is the survival function of xi?
It is known that the survival function of Xi:n can be written as (see [Gupta (2002, p. 839)])P (Xi:n > t) = i−1∑ j=0 (−1)i−j−1 ( n j )( n− j − 1 n− i ) F n−j (t),from which its density function isfi:n(t) = hX(t) i−1∑ j=0 (−1)i−j−1 ( n j )( n− j − 1 n− i ) (n − j)F n−j(t),where hX(t) is the hazard rate function of X.
Q9. What is the survival function of TX(p)?
From (1.1) the survival function of TX(p) can be written asF TX(p)(t) = n∑ i=1 pi i−1∑ j=0( nj) F j(t)F n−j (t)= n−1∑ j=0⎛ ⎝ n∑i=j+1pi⎞ ⎠(nj) F j(t)F n−j (t), (2.1)by changing the order of summation.