The integral of a symmetric unimodal function over a symmetric convex set and some probability inequalities
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Additional excerpts
...Anderson in [1], Fefferman, Jodeit and Perlman in [6] show that if μ1 = μ2, R1 d = R2, and ξΣ1ξ ≤ ξΣ2ξ, ∀ ξ ∈ R, then E(ψ(X)) ≤ E(ψ(Y )) for all symmetric and convex functions ψ : R 7→ R, such that the expectations exist....
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13 citations
12 citations
Cites methods from "The integral of a symmetric unimoda..."
...Moreover, it is obvious from the definition of the Voronoi cell C(0) that for every c ∈ [1, 2), C(0) ⊂ [ ∪x∈ΦB ( 1 c · x, ( 1 c − 1 2 ) · L )]c ....
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...For every fixed ε > 0 and c ∈ [1, 2), we obtain ∫ +∞...
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...since the set Au, u > 0, is convex and symmetric, we may apply Anderson’s lemma [1] which gives P {W ∈ Au + x} ≤ P {W ∈ Au} ....
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12 citations
12 citations
References
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"The integral of a symmetric unimoda..." refers background in this paper
...In Theorem 1 the equality in (1) holds for k<l if and only if, for every u, (E+y)r\Ku=Er\Ku-\-y....
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...It will be noticed that we obtain strict inequality in (1) if and only if for at least one u, H(u)>H*(u) (because H(u) is continuous on the left)....
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"The integral of a symmetric unimoda..." refers background in this paper
...f ud[H*(u) - H(u)} = b[H*(b) - H(b)] - a[H*(a) - H(a)} (3) " + f [(H(u) - H*(u)]du....
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...J a Since/(x) has a finite integral over E, bH(b)—>0 as b—>oo and hence also bH*(b)—>0 as b—*<x>; therefore the first term on the right in (3) can be made arbitrarily small in absolute value....
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