The integral of a symmetric unimodal function over a symmetric convex set and some probability inequalities
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...6) and Anderson’s inequality (see [2]), we derive P(tp) ≤ c2,4 R−1 [ min { min 0≤j≤p−1 |tp − t − z|, |x− y| }]−α ....
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8 citations
8 citations
7 citations
Additional excerpts
...According to Anderson’s theorem, for any convex setE, if f(x) = f(−x) and ∫ E f(x)dx < ∞, then ∫ E f(x+ky)dx ≥ ∫ E f(x+y)dx, 0 ≤ k ≤ 1 [Anderson, 1955]....
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"The integral of a symmetric unimoda..." refers background in this paper
...In Theorem 1 the equality in (1) holds for k<l if and only if, for every u, (E+y)r\Ku=Er\Ku-\-y....
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...It will be noticed that we obtain strict inequality in (1) if and only if for at least one u, H(u)>H*(u) (because H(u) is continuous on the left)....
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"The integral of a symmetric unimoda..." refers background in this paper
...f ud[H*(u) - H(u)} = b[H*(b) - H(b)] - a[H*(a) - H(a)} (3) " + f [(H(u) - H*(u)]du....
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...J a Since/(x) has a finite integral over E, bH(b)—>0 as b—>oo and hence also bH*(b)—>0 as b—*<x>; therefore the first term on the right in (3) can be made arbitrarily small in absolute value....
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