The integral of a symmetric unimodal function over a symmetric convex set and some probability inequalities
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...e variable jS 1 + ˆ q1j. Consequently, it follows from a standard that median(F n) ! P median(F), and then mb q qkxk q ! P median(F) =: 1=c1 >0: (124) (Note that it follows from Anderson’s Lemma [And55] that median(F) median(jS1j), which is clearly positive.) Altogether, we have veried that btinitial = 1=mb q satises btinitial qkxk q ! P c1. Combining the previous limit with line (41) and Theorem...
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Cites background from "The integral of a symmetric unimoda..."
...Thus by the fact that the conditional distributions of the Gaussian process is almost surely Gaussian, and by Anderson’s inequality (see Anderson [1]) and the definition of C8, we obtain P2(k)≤ P ( N(0,1)≤ (1− μ) √ 2(a1 − δ) log(1 + r k ) ) ,...
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...Thus by the fact that the conditional distributions of the Gaussian process is almost surely Gaussian, and by Anderson’s inequality (see Anderson [1]) and the definition of C8, we obtain P2(k)≤ P ( N(0,1)≤ (1− µ) √ 2(a1 − δ) log(1 + r−1k ) ) , where N(0,1) denotes a standard normal random variable....
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"The integral of a symmetric unimoda..." refers background in this paper
...In Theorem 1 the equality in (1) holds for k<l if and only if, for every u, (E+y)r\Ku=Er\Ku-\-y....
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...It will be noticed that we obtain strict inequality in (1) if and only if for at least one u, H(u)>H*(u) (because H(u) is continuous on the left)....
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"The integral of a symmetric unimoda..." refers background in this paper
...f ud[H*(u) - H(u)} = b[H*(b) - H(b)] - a[H*(a) - H(a)} (3) " + f [(H(u) - H*(u)]du....
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...J a Since/(x) has a finite integral over E, bH(b)—>0 as b—>oo and hence also bH*(b)—>0 as b—*<x>; therefore the first term on the right in (3) can be made arbitrarily small in absolute value....
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