Void lattice formation as a nonequilibrium phase transition
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Citations
Spatial ordering of nano-dislocation loops in ion-irradiated materials
Transport, Dissociation and Rotation of Small Self-interstitial Atom Clusters in Tungsten
Diffuse interface modeling of void growth in irradiated materials. Mathematical, thermodynamic and atomistic perspectives
Detection of one-dimensional migration of single self-interstitial atoms in tungsten using high-voltage electron microscopy
Radiation-induced void formation and ordering in Ta-W alloys
References
The primary damage state in fcc, bcc and hcp metals as seen in molecular dynamics simulations
Stability and mobility of defect clusters and dislocation loops in metals
Production bias due to clustering of point defects in irradiation-induced cascades
Observations of a regular void array in high purity molybdenum irradiated with 2 MeV nitrogen ions.
Invited review article ordering of voids and gas bubbles in radiation environments
Related Papers (5)
Kinetic Monte Carlo simulations of void lattice formation during irradiation
Frequently Asked Questions (13)
Q2. how much flux is proportional to the surface area of the void?
Since the flux of the self-interstitials moving one dimensionally along the crystallographic close-packed directions towards a void is proportional to the surface area of the void, voids with smaller sizes receive smaller 1D flux of interstitials.
Q3. How many NRT dpa can be observed at which void density?
As irradiation proceeds, void density can indeed reach experimental values at which void lattices can be observed i.e., up to N 1023 m−3 within just a few NRT dpa.42
Q4. What is the mechanism of the shrinkage of nonaligned voids?
When i0 Z−1 , stochastic fluctuations do not play an important role in the evolution of the void ensemble, and, consequently, there is no mechanism via which the shrinkage of nonaligned voids can occur.
Q5. How is the average swelling rate for a void?
even for the voids with the radii as small as 1–2 nm the average swelling rate S /Kt is less than 3 10−3 /NRT dpa,27 which is translated into i 10 −2 G /K 0.3,45 .
Q6. What is the main driving force for void swelling in the peak swelling regime?
On the other hand, if a significant fraction of interstitials generated in collision cascades is in the form of immobile clusters, such as in fcc copper,20–23 the major driving force for void swelling in the peak swelling regime comes from the “production bias.
Q7. What is the effect of noise on the growth behavior of the random voids?
As it is shown in the present paper, if i is less than 1% the noise in the point-defect fluxes has a profound effect on the growth behavior of the random voids when the swelling rate drops below 0.1%/NRT dpa e.g., due to a high density of voids .
Q8. What is the probability of the diffusion motion of a dumbbell at elevated temperatures?
at elevated temperatures the diffusion motion of such dumbbell will be mostly three dimensional, although a low probability of the occasional one-dimensional diffusion for sufficiently long distances may still exist.
Q9. What is the condition for the RIF voids to be the dominant sinks?
Using Eq. 25 , the condition for the RIF voids to be the dominant point-defect sinks, i.e., kRIF 2 /kc 2 1, can be written in the formS c Ndqns RIF , 26whereS c 6 cexp Ĩ s/ c / cc/ s 1 + c/ s S . 27Note that according to Eqs. 14 and 15 , the integral Ĩ depends only on the ratio s / c, which can be expressed in terms of Sc s= rs RIFkcNd 4 1 + 1 − i0 2 3SNd 4 1 + 1 − i0 2 ,28if the RIF voids are the dominant sinks.
Q10. What is the way to achieve a low swelling rate?
At this point, the authors note that, although a high void-number density due to a low nucleation barrier produces a low swelling rate and a small average void size, this is by no means the only way such a condition can be achieved.
Q11. How does the flux of static crowdions be obtained?
the flux of static crowdions, i.e., metastable interstitials that undergoes thermal conversion to the stable dumbbells,5,18 can be obtained directly from Eq. 31 , and Eq. 10 becomesdn dt 1D interstitials = −2 r2 i0G= −3 i0G2a n2/3 .32
Q12. What is the probability of void nucleation in the RIF?
even if the total RIF volume is smaller than 1% of the total volume S 1% , the probability of void nucleation in this volume can still be higher than outside of it.
Q13. What is the capture probability for a 1D random walker?
The capture probability Pa for a 1D random walker between the two traps is calculated in Appendix B. Averaged over the initial position of the 1D diffuser, this probability is the same for each trap, and is given byPa = l tanh l/2 , 31where l is the distance between the traps, = D1 c 1/2 is the mean free path of the random walker, and D1 and c are its one-dimensional diffusion coefficient and the mean lifetime, respectively.