Q2. How much of the k-step ahead prediction error variance of real output is a ?
Monetary policy shocks account for probably less than twentyfive percent of the k-step ahead prediction error variance of real output, and may easily account for less than three percent.
Q3. What is the reason for the variation in prices and interest rates?
The remaining variations in prices and interest rates may still be due to monetary policy, but then it needs to be due to the endogenous part of monetary policy: by systematically responding to shocks elsewhere, monetary policy may end up being responsible for 100% of the movements in prices.
Q4. How does the monetary policy shock affect real output?
A one-standard deviation monetary policy shock may leave output unchanged or may drive output up or down by up to 0.2 percent in most cases, thus possibly triggering fairly sizeable movements of unknown sign.
Q5. How does the Federal Funds Rate react to a monetary policy shock?
4. The Federal Funds Rate reacts large and positively immediately, typically rising by 30 basis points, then reversing course within a year, ultimately dropping by 10 basis points.
Q6. What is the average GDP price deflator?
The GDP price deflator reacts very sluggishly, with prices dropping by about 0.2 percent within a year, and dropping by 0.5 percent within five years.
Q7. What is the impulse vector corresponding to monetary policy shocks?
To identify the impulse vector corresponding to monetary policy shocks, the authors impose, that a contractionary policy shock does not lead to an increase in prices or in nonborrowed reserves and does not lead to a decrease in the federal funds rate.
Q8. What is the largest fraction of variation explained by monetary policy?
For interest rates, the largest fraction of variation explained by monetary policy is at the short horizon, providing further support to the view, that11monetary policy shocks are accidental errors by the Federal Reserve Bank, which are quickly reversed.
Q9. What is the drawback of the pure-sign-restriction approach?
As a drawback, the pure-sign-restriction is, in effect, simultaneously an estimation of the reduced-form VAR alongside the impulse vector: VAR parameter draws, which do not permit any impulse vector to satisfy the imposed sign restrictions, are discarded as “impossible”.
Q10. What is the simplest way to calculate the impulse response?
a is an impulse vector if and only if there are coefficients αi, i = 1, . . . ,m with5∑m i=1 α 2 i = 1, so thata = m∑ i=1 ( αi √ λi ) xi (3)Given an impulse vector a, it is easy to calculate the appropriate impulse response, see appendix B for details.