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Showing papers on "Probability-generating function published in 1970"



Journal ArticleDOI
TL;DR: All minimal polygons have the vertices between two noncollinear sides in the same position and differ only in the position of vertices corresponding to nonactive constraints: the minimal reduced polygon is unique.
Abstract: We now prove separately the inequality for every term of the summation. Let us assume the thesis is wrong > ([(XLk+:-Xi,k) 2 + (yLk+:-yl.~)~] t \"Jr [(X2.k+x-X2,k) 2 + (y2,k+l-Y2,k)2]t). which is contradictory. We can have equality to zero iff i.e. if all the corresponding sides of the two polygons are parallel. (e, d) We must prove that the minimal polygon has at least one vertex on the boundary of the corresponding domain. In fact, consider a minimal polygon: there will be at least a couple of adjaeent noncollinear sides. The corresponding vertex must lie on the boundary, otherwise a shorter perimeter polygon could be found (see Figure 7 (a), (b)). Furthermore, from simple geometrical considerations it can be deduced that the normal to the boundary must bisect the angle between the two adjacent sides (Figure 7 (b)). Conversely, if a constraint is not active, i.e. a vertex is not on the boundary, the adjacent sides in the minimal polygon must be collinear. (e) From the convexity properties of the domain D and of the function f it can be deduced that: (i) all local minima are global; (ii) any convex linear combination of minima is a minimum as well; (iii) Jensen's relation (3) applied to two minima obviously holds with equality. We have proved in (b) that in our ease Jensen's relation holds with equality if and only if the corresponding sides of the two polygons are parallel. Now assume to have found a (global) minimum: any vertex between two noncollineax sides will satisfy the bisection property proved in (d). If no straight line segments axe present on the boundary of domain C (e.g. if domain C is a circle), it is not possible to translate two adjacent noncollinear sides still satisfying the bisection property. Therefore, all minimal polygons have the vertices between two noncollinear sides in the same position. Thus they differ only in the position of vertices corresponding to nonactive constraints: the minimal reduced polygon is unique. * The work forms part of a research program supported by the Bundesministerium fiir wissenschaftliche Forsehung and the Fritz ter Meer-Stiftung. c o m m e n t If a Laplace transform P(s) is given in the form of a real procedure, L/nv produces an approximate value Fa of the inverse F(t) at T. Fa is evaluated according to Fa =-~-~=: N must be even. Since the V~ depend on …

16 citations


ReportDOI
01 May 1970
TL;DR: The paper describes a method to control both autocorrelation and probability density of random time series simultaneously, which is desirable when seeking solutions through simulation.
Abstract: : In many engineering design problems it is possible to collect data of the environmental disturbances which are acting upon the systems. This data can be analyzed by determining its autocorrelation and probability density function. When seeking solutions through simulation it is desirable to be able to generate random time series having a predetermined autocorrelation and probability density. The paper describes a method to control both simultaneously.

4 citations



Journal ArticleDOI
TL;DR: In this article, the random radius of convergence of a power series f(z) = ⌆ aizi is investigated in a homogeneous random process setting, where the sequence is exchangeable and the variance of the marginal distributions exists.
Abstract: Power series f(z) =⌆ aizi are considered, where the sequence {ai} forms a homogeneous random process. If the sequence is exchangeable and the variance of the marginal distributions exists, it is proved that r, the random radius of convergence of f(z), takes the values 0 and 1. If the sequence is a second order stationary time series then r=1 with probability 1. If {ai} is a regular denumerable Markov chain, it can be proved that r=c≲=1 with probability 1, but both c=0 and c=1 can arise. A number of criteria are given for deciding the value of c in this situation.

1 citations