The bideterministic concatenation product
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Citations
Syntactic semigroups
Finite semigroups and recognizable languages: an introduction
An Explicit Formula for the Intersection of Two Polynomials of Regular Languages
Two algebraic approaches to variants of the concatenation product
References
Automata, Languages, and Machines
On finite monoids having only trivial subgroups
Algebraic theory of machines, languages, and semigroups,
Related Papers (5)
Frequently Asked Questions (14)
Q2. What is the syntactic congruence of L?
The syntactic congruence of L is the equivalence ∼L on A∗ defined byu ∼L v if and only if, for every x, y ∈ A ∗ (xuy ∈ L ⇐⇒ xvy ∈ L).
Q3. What is the proof for the relational morphism between monoids?
There is a relational morphism τ : M → N with N ∈ Wand such that eτ−1 ∈ V for all idempotents e ∈ N }Let A be a finite set, called the alphabet, whose elements are letters.
Q4. What is the deterministic product of the free monoid A?
A ∗ | u = u0au1 for some u0 ∈ L0 and u1 ∈ L1}Unambiguous, left and right deterministic products were introduced by Schützenberger.
Q5. What is the smallest boolean algebra containing the languages of the form B?
for every alphabet A, V(A∗) is the smallest boolean algebra containing the languages of the form B∗, where B is a subset of A and closed under bideterministic product.
Q6. What is the formula for determining the product P?
if for instance the product P was not deterministic, then there would be a word u ∈ P with a factorization of the form u = u0au ′au1 with u0a, u0au ′a ∈ β−1(K0x −1 0 )a and u′au1, u1 ∈ β−1(x −1 1 K1).
Q7. how does s1s2 show that s1 is regular?
Then s1 · · · si−1 R s1 · · · si−1(sisi+1) and one may apply the induction hypothesis to the sequence s1, . . . , si−1, (sisi+1), si+2, . . . , sn to show that s1s2 · · · sn is regular.
Q8. What is the minimum ideal of a monoid?
If the minimal ideal G of a monoid M is a group, then M is a submonoid of (M/G) × G.Proposition 4.9 Suppose that a monoid M has a zero and a unique 0-minimal ideal J .
Q9. What is the morphism of a monoid?
Since x ∼ϕ y implies ϕ(x) = ϕ(y), there exists a surjective morphism π : M̂ → M such that the following diagram commutes:M̂MA∗ϕϕ̂πMore generally, a monoid M̂ is said to be an expansion of a monoid M if there exists a free monoid A∗ and a surjective morphism ϕ :
Q10. What is the result of the induction on Card(M)?
Thus M̂ ∈ Wand Ŵ = W. Since V ⊂ W, it follows that V̄ ⊂ W. Conversely, let M be a monoid in W. The authors show by induction on Card(M) that M ∈ V̄.
Q11. What is the morphism of the free monoid?
there exist a morphism α : A∗ → M̂ such that L = α−1(P ), where P = α(L), and a surjective morphism ϕ : B∗ → M which defines the expansion ϕ̂ : B∗ → M̂ .
Q12. what is the morphism of a monoid?
Example 2.1 Let ϕ : {a, b}∗ → U1 = {1, 0} be the surjective monoid morphism defined by ϕ(a) = 1 and ϕ(b) = 0. Then (aa, b, 1) is a good factorization.
Q13. What is the simplest way to prove that a factorization is a good one?
Define a relation ∼ϕ on A∗, by setting, for each x, y ∈ A∗, x ∼ϕ y if and only if the following three conditions are satisfied:(1) ϕ(x) = ϕ(y),(2) each good factorization of x is equivalent to some good factorization of y,(3) each good factorization of y is equivalent to some good factorization of x.
Q14. What is the simplest way to extend the theorem?
Theorem 4.11 can be extended as follows :Theorem 4.12 Let H be a variety of groups and let Sl(H) be the variety of monoids which are semilattices of groups of the variety H. Then Sl(H) is the variety of monoids with commuting idempotents whose regular J -classes are groups of the variety H.Proof.