On the variation with flux and frequency of the core loss coefficients in electrical machines
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Citations
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Estimation of Iron Losses in Induction Motors: Calculation Method, Results, and Analysis
A General Model to Predict the Iron Losses in PWM Inverter-Fed Induction Motors
High-Speed Electric Machines: Challenges and Design Considerations
References
General properties of power losses in soft ferromagnetic materials
An improved approach to power losses in magnetic laminations under nonsinusoidal induction waveform
Predicting iron losses in soft magnetic materials with arbitrary voltage supply: an engineering approach
An improved estimation of iron losses in rotating electrical machines
An improved formula for lamination core loss calculations in machines operating with high frequency and high flux density excitation
Related Papers (5)
Frequently Asked Questions (14)
Q2. What is the term for the hysteresis component?
The last term corresponds to the excess or anomalous loss component, which is influenced by intricate phenomena, such as microstructural interactions, magnetic anisotropy, nonhomogenous locally induced eddy currents.
Q3. What is the corresponding value for the eddy-current component?
Under sinusoidal alternating excitation, which is typical for form-factor-controlled Epstein frame measurements, the specific core losses wFe in watts per pound (or watts per kilogram) can be expressed bywFe = khfBα + kef2B2 + kaf1.5B1.5 (1)where the first right-hand term stands for the hysteresis loss component and the second for the eddy-current loss component.
Q4. What is the repeatability of the hysteresisgraph?
The repeatability of the hysteresisgraph is certified by the instrument manufacturer at 0.1% for magnetic field measurements and 0.2% for power loss measurements.
Q5. What is the effect of the open-circuit core loss model?
the flux density in the back iron, which accounts for approximately a third of the total stator core loss, is partially exposed to rotational flux with rather significant radial and tangential components (Fig. 17), which can produce rotational core losses [21].
Q6. What is the reason for the instabilities of the magnetic domains?
One possible explanation can lay in the fact that the area of the quasi-static magnetization loop, which is a measure of the hysteresis losses, is influenced by the dynamic losses [5], [6] and that the instability of the magnetic domains at the microscopic level is a nonlinear and complicated function of magnetization and frequency.
Q7. How many variations can be set to a given frequency?
The plot of log a against induction at a set frequency indicates three intervals of different variation types, which, for the example shown in Fig. 7, can be approximately set to induction ranges of 0.0–0.7, 0.7–1.4, and 1.4–2 T.
Q8. What is the reason why the oscillating errors in Fig. 10 are?
Oscillating errors as those illustrated in Fig. 10 also provide an interesting explanation as to why, sometimes, the calculations employing a conventional model with constant coefficients are not entirely out of proportion; provided that the flux density around which the error oscillations occur is corresponding to an “average”operating point of the magnetic circuit, overall, the overestimation and the underestimation for different regions of the core will tend to cancel each other through a more or less fortunate arrangement.
Q9. How many points can be calculated by quadratic fitting?
As the first step of the procedure developed in order to identify the values of the coefficients, (1) is divided by the frequency resulting inwFe f= a + b √ f + c (√ f )2(2)wherea = khBα b = kaB1.5 c = keB2. (3)For any induction B at which measurements were taken, the coefficients of the aforementioned polynomial in √ f can be calculated by quadratic fitting based on a minimum of three points (Fig. 4).
Q10. What is the phenomenological aspect of the new specific core loss model?
Inasmuch as the numerical validity of the new specific core loss model is based on a systematic mathematical algorithm to identify coefficients and is proven through the small errors to measurements, its phenomenological aspects are open to debate.
Q11. What is the coefficient a of a given frequency?
The coefficient a represents the ratio of hysteresis loss and frequency, which is calculated from (2) by substituting the values of b and c from (3) and making use of the analytical estimators (4) and (5), which greatly reduce numerical instabilities.
Q12. What is the example of the curve-fitting procedure?
The model was also used to estimate losses at frequencies not employed in the curve-fitting procedure, and an example is provided in Fig.
Q13. What are the classical values of ke for the materials considered?
For the materials considered, SPA, SPB, and M43, the classical values of ke correspond on the nonlinear curves shown in Fig. 5 to an induction of approximately 1.3, 1.5, and 1.7 T, respectively.
Q14. What is the way to fit the coefficients of ke and ka?
The use of a lower order polynomial in (4) and (5) is not recommended, as it leads to a poorer data fit with a considerably lower r2.