Analysis of Generalized Exponential Distribution Under Adaptive Type-II Progressive Hybrid Censored Competing Risks Data
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Citations
Estimation of the inverse Weibull parameters under adaptive type-II progressive hybrid censoring scheme
Analysis of Weibull Distribution Under Adaptive Type-II Progressive Hybrid Censoring Scheme
Bayesian analysis of Weibull distribution based on progressive type-II censored competing risks data with binomial removals
Estimation of the extended Weibull parameters and acceleration factors in the step-stress accelerated life tests under an adaptive progressively hybrid censoring data
Bayesian survival analysis for adaptive Type-II progressive hybrid censored Hjorth data
References
Estimating the Dimension of a Model
Estimating the dimension of a model
Fitting autoregressive models for prediction
Generalized Exponential Distributions
Maximum Likelihood Estimation in the Weibull Distribution Based On Complete and On Censored Samples
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Frequently Asked Questions (11)
Q2. What is the drawback of the T-II PHCS?
The drawback of the T-II PHCS is that the effective number of failures is random and it can be a very small number (even equal to zero), so that usual statistical inference procedures will not be applicable or they will have low efficiency.
Q3. What is the probability ratio test statistic for the ED?
Under the null hypothesis the log-likelihood ratio test statistic is 02ln 2 ( ) ( )L where ( ) and 0( ) are the log-likelihood functions under 1H and 0H , respectively.
Q4. What are the main objectives of this paper?
They have also discussed confidence intervals for the model parameters through the use of the asymptotic distribution of the MLEs as well as by the bootstrap method.
Q5. What is the probability ratio of the ED?
the authors can write the log-likelihood ratio test statistics as follows 2L GED ED where ED and GED are the log-likelihood functions under 0H and 1H , respectively, after replacing the unknown parameters with their MLE.
Q6. What is the likelihood ratio test used to test the adequacy of generalized exponential?
Because the ED can be derived as a special case of the GED, the likelihood ratio test will be used to test the adequacy of generalized exponential distributions competing risks.
Q7. How many observations were left in the analysis?
The cause of death for each mouse was determined by reticulum cell sarcoma as cause 1 and other causes of death as cause 2, there were 77n observations remain in the analysis.
Q8. What is the probability density function for failure?
The cumulative distribution function ( )kF x andfailure hazard function ( )kh x have the form .( ) 1 k k x kF x e (2)and 1 1 . . .( ) . . .
Q9. What is the latent failure time of the i-th unit?
The authors have 1 2min ,i i iX X X for 1,...,i n ,where , 1,2kiX k , denotes the latent failure time of the i-th unit under the k-th cause of failure.
Q10. What is the probability of a GED failure?
When 1 2 1 , the MLE's of 1 and 2 and the relative risk rates 1 and 2 , corresponds to the results of the exponential distribution obtained by Hemmati and Khorram [11], when the cause of failure is known.
Q11. What is the MLE of the relative risk rates?
According to the invariance property of the MLE, the MLE of the relative risk rates 1 , can be obtained by replacing the MLE of 1 2 1, , and 2 in (9).