Multicarrier Communication Over Underwater Acoustic Channels With Nonuniform Doppler Shifts
read more
Citations
Underwater Optical Wireless Communication
Sparse channel estimation for multicarrier underwater acoustic communication: From subspace methods to compressed sensing
A Survey of Architectures and Localization Techniques for Underwater Acoustic Sensor Networks
Prospects and problems of wireless communication for underwater sensor networks
MIMO-OFDM for High-Rate Underwater Acoustic Communications
References
Information Theory, Inference and Learning Algorithms
Information theory, inference, and learning algorithms
Wireless Communications
Wireless multicarrier communications
OFDM for Wireless Communications Systems
Related Papers (5)
Underwater acoustic communication channels: Propagation models and statistical characterization
Frequently Asked Questions (16)
Q2. What have the authors stated for future works in "Multicarrier communication over underwater acoustic channels with nonuniform doppler shifts" ?
Future research will address several topics, including shortening methods for channels whose delay spread is longer than the guard interval, extension of resampling to generalized time-varying filtering for channels with different Doppler scaling factors on different paths, and multi-input multi-output ( MIMO ) techniques [ 29 ] – [ 31 ].
Q3. What are the main topics of future research?
Future research will address several topics, including shortening methods for channels whose delay spread is longer than the guard interval, extension of resampling to generalized time-varying filtering for channels with different Doppler scaling factors on different paths, and multi-input multi-output (MIMO) techniques [29]–[31].
Q4. What is the BER performance of the packets?
Since the channel condition was particularly severe in this test, both coding (rate 2/3) and multi-channel combining were necessary to improve the BER performance.
Q5. What is the cost function of the null subcarriers?
The energy of the null subcarriers is used as the cost functionJ( ) = ∑m∈SN|fHmΓH( )z|2. (14)If the receiver compensates the data samples with the correct CFO, the null subcarriers will not see the ICI spilled over from neighboring data subcarriers.
Q6. How does the receiver estimate the time duration of a packet?
2. By cross-correlating the received signal with the known preamble and postamble, the receiver estimates the time duration of a packet, T̂rx.
Q7. How many ms are the blocks in the OFDM?
The OFDM block durations are T = 42.67, 85.33, 170.67 ms in their experiments when the numbers of subcarriers are 512, 1024, 2048, respectively.
Q8. What is the effect of the noise realizations on the CFO?
5) Note that fewer null subcarriers are available in the K = 512 case than the K = 1024 and K = 2048 cases, and hence the CFO estimation is more affected by the noise realizations.
Q9. What is the frequency response of the mth subcarrier?
3. Each data burst consists of three packets, with K = 512, K = 1024, and K = 2048, respectivelyfrequency response, and the additive noise observed at the mth subcarrier of the rth element.
Q10. What is the averaged BER for the low speed and high speed cases?
With MRC, the uncoded BERs averaged over the packet are 2 · 10−2 and 1.7 · 10−2 for the low speed and high speed cases, respectively.
Q11. How many BERs are averaged over the packet?
With K = 1024, the BERs averaged over the packet (packet #2) after MRC and coding is 1.1 · 10−2 and 6.5 · 10−2 for the2 4 6 8 10 12 14 16010 −410 −310 −210 −110 0OFDM block indexB itE rror Rat euncoded, element 1 coded, element 1 uncoded, MRC coded, MRCFig. 18. The BERs for each OFDM block, the low speed case, K = 2048.
Q12. How was the relative speed between the transmitter and the receiver estimated?
Based on each Doppler scaling factor â, the relative speed between the transmitter and the receiver was estimated as v̂ = â · c, using a nominal sound speed of c = 1500 m/s.
Q13. What is the average BER for the low speed and high speed cases?
After rate 2/3coding, the BERs averaged over the packet are 1.6 · 10−3 and 5.8·10−3 for the low speed and high speed cases, respectively.
Q14. How many ms is the delay between the bottom bounce and the direct path?
This conjecture is supported by a rough computation based on the channel geometry:• Case 1: suppose that the distance is 400m, the depth is 12 m, then the delay between the bottom bounce and the direct path is (2 · √ 2002 + 122 − 400)/1500 = 0.48 ms. • Case 2: suppose that the transmitter is now 150m from the receiver, and the depth is 12m.
Q15. What is the time duration of a packet at the transmitter side?
The time duration of this packet at the transmitter side is Ttr. By comparing T̂rx with Ttx, the receiver infers how the received signal has been compressed or dilated by the channel:T̂rx = Ttx 1 + â ⇒ â = Ttx T̂rx − 1. (13)The receiver then resamples the packet with a resampling factor b = â used in (7).
Q16. What is the difference between the frequency of the OFDM signal and the center frequency?
Since the bandwidth of the OFDM signal is comparable to the center frequency, the Doppler-induced frequency shifts on different OFDM subcarriers differ considerably; i.e., the narrowband assumption does not hold.