Efficient dynamical correction of the transition state theory rate estimate for a flat energy barrier
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Citations
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References
A climbing image nudged elastic band method for finding saddle points and minimum energy paths
Brownian motion in a field of force and the diffusion model of chemical reactions
Improved tangent estimate in the nudged elastic band method for finding minimum energy paths and saddle points
Reaction-rate theory: fifty years after Kramers
Characterization of individual polynucleotide molecules using a membrane channel
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Frequently Asked Questions (12)
Q2. Why does the HTST rate show a peak at N = 20?
2.The HTST rate shows a peak at N = 20 which is due to the smallest positive eigenvalue at the saddle point approaching zero and causing divergence in the rate estimate, Eq. (9).
Q3. How many hyperplanes were used to obtain the escape rate for efficiency analysis?
To obtain the statistical error in the escape rate for efficiency analysis, the FFS calculation was repeated with 10 000 trajectories started from each hyperplane and the standard deviation of the result computed.
Q4. what is the resulting contribution to the force on the polymer?
The interaction between adjacent beads is given by a harmonic potential functionU = N−1 n=1 (K/2)(rn − rn+1)2. (2)The resulting contribution to the force on bead n is− ∇nU = −K(rn−1 + rn+1 − 2rn).
Q5. What is the HTST estimate of the escape rate?
The evaluation of the HTST estimate of the escape rate requires finding the first order saddle point on the energy surface defining the transition state and evaluating the vibrational frequencies from eigenvalues of the Hessian at the saddle point and the initial state minimum.
Q6. How many trajectories do the forward flux method use?
The forward flux method, however, is computationally more demanding because it relies on trajectories that go uphill in energy, and only a small fraction of the trial trajectories do so.
Q7. What is the HTST estimate of the transition rate?
The HTST estimate of the transition rate is13,14RHTST = 12π √ µ⊥N i=1 λ0 iNi=2 λ ‡ ie−∆E/kBT , (9)where µ⊥ is the reduced mass, and λ0i and λ ‡ i are the eigenvalues of the Hessian matrices at the minimum and at the saddle point, respectively.
Q8. What is the probability of the system reaching a plane n?
42The rate constant is obtained in FFS as40RFFS = Φ̄I,0 h̄I P(λn, λ0), (7)where Φ̄I,0/h̄I is the initial flux across the first plane λ0 towards the final state and P(λn |λ0) is the probability that the system reaches plane λn, given it was initially at λ0.
Q9. How many times can a correction be made for the transition state theory?
By carrying out calculations of short time trajectories starting at the transition state, a correction for this approximation can be made.
Q10. Why does the HTST estimate of the escape rate saturate?
This is because the height of the effective energy barrier, the maximum along the MEP, saturates as the barrier starts to flatten out as shown in Fig.
Q11. How many extra planes were added to the region where the potential gradient is steep?
For polymers of length N = 64, six additional planes were added to the region where the potential gradient is steep (see Fig. 3) and the forward flux P(λi+1|λi) is small.
Q12. How can the efficiency of the FFS method be improved?
The efficiency of FFS can be optimised by adjusting the number and location of the hyperplanes and adjusting the number of trial runs for each plane.