Quantum magnetism without lattices in strongly interacting one-dimensional spinor gases
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Citations
Antiferromagnetic heisenberg spin chain of a few cold atoms in a one-dimensional trap
Strongly interacting confined quantum systems in one dimension
A unified ab initio approach to the correlated quantum dynamics of ultracold fermionic and bosonic mixtures.
Colloquium : Atomic spin chains on surfaces
One-dimensional mixtures of several ultracold atoms: a review
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Frequently Asked Questions (12)
Q2. How can the authors prepare nontrivial initial spin states?
magnetic-field gradients may be employed to prepare nontrivial initial spin states (e.g., helical states), and to rotate individual spins in combination with radio-frequency fields.
Q3. What is the eigenfunction of a multicomponent 1D system?
At infinite repulsion a multicomponent 1D system behaves as a spinless Fermi gas characterized by states with a given spatial ordering of the particles.
Q4. What is the significance of a SU(N) exchange Hamiltonian?
In particular, a spin-3/2 system would realize an SU(4) exchange Hamiltonian, which is of relevance in spin-orbital models of transition-metal oxides.
Q5. What is the procedure for detecting the spin orientation of the fermions?
the spin-up (-down) fermions are removed with a resonant light pulse, and afterwards the occupancies of the remaining spin-down (-up) fermions are probed using the tunneling technique [47].
Q6. What is the eigenfunction of a multicomponent Bose system?
Multicomponent trapped Fermi or Bose systems with an infinite contact repulsion may be exactly solved [20] through a generalization of Girardeau’s Bose-Fermi mapping for spinless bosons [18].
Q7. What is the effect of a spin-dependent external potential?
A spin-dependent external potential, such as, e.g., a B-field gradient, violates spin conservation, lifting the spin degeneracy at J = 0 [28,29] (inset of Fig. 3).
Q8. Why is the AF ground state for g 0 adiabatically transformed?
In particular, the AF ground state for g > 0 may be adiabatically transformed into the F ground state for g < 0 due to the avoided crossing opened by the B-field gradient, as suggested in Ref. [29].
Q9. What is the simplest way to solve the exchange constants of a multicomponent trapped?
The effective interaction Hamiltonian of the spin chain reads (see Appendix A for the derivation)3Hs = (EF − N−1∑ i=1 Ji) 1 ±N−1∑ i=1 JiPi,i+1, (6)where Pi,i+1 denotes the permutation of the spin of neighboring particles, the + (−) sign applies to fermions (bosons), and the nearest-neighbor exchange constants are given byJi = N ! 4m2g∫ dz1 · · · dzNδ(zi − zi+1)θ (z1, . . . ,zN ) ∣∣∣∣∂ψF∂zi ∣∣∣∣ 2 .(7)The exact calculation of the exchange constants Ji requires the solution of multidimensional integrals of growing complexity with increasing N , which is in practice possible only for small N .4 Fortunately, an accurate approximation of the exchange constants, which becomes even more accurate for growing N , is provided by the expressionJi = 4π2n3TF(zi)3m2g , (8)where nTF is the Thomas-Fermi (TF) profile of the density and zi is the center of mass of the ith and (i + 1)th particle density, ρ(i)(z) and ρ(i+1)(z) (see Appendix B).
Q10. What is the probability to find the ith particle?
In particular, the density distribution of the mth component is given by [20]ρm(z) = ∑iρ(i)m ρ (i)(z) (3)with the probability that the magnetization of the ith spin equals m,ρ(i)m = ∑m1,...,mN|〈m1, . . . ,mN |χ〉|2δm,mi , (4)and the probability to find the ith particle (with whatever spin) at position z,ρ(i)(z) = N ! ∫dz1 · · · dzNδ(z − zi)θ (z1, . . . ,zN )|ψF |2. (5)The continuous spin density ρm(z) is hence fully characterized by the N -tuple (ρ(1)m , . . . ,ρ (N) m ), as illustrated in Fig.
Q11. What is the effect of a gradient on the effective spin interaction Hamiltonian?
Such a gradient adds to the effective spin interaction Hamiltonian (6) a term VG = (G/l) ∑ i〈z〉iσ (i)z with 〈z〉i = ∫ dzzρ(i)(z) and the oscillatorlength l (Appendix D).
Q12. What is the difference between the adiabatic sweep and the f ground state?
This implies that an adiabatic sweep becomes more involved for larger N , since −J/G has to be increased much more slowly than / min in an increasing region of the Tonks regime.