Q2. What is the oxidation state of a lanthanide metal?
A bimetallic, mixed-ligand metallocene/openedcrypt complex of Sm2+, [Sm(C16H32N2O6-j 2O:j2O0)SmCp0 02], was obtained by KC8 reduction of Cp0 02Sm(THF) [Cp0 0 = C5H3(SiMe3)2]in the presence of crypt.
Q3. What is the oxidation state of sm2+?
10 In addition, Ln(C6H3tBu3-1,3,5)2 complexes have been isolated for Ln = Nd, Tb, Dy, Ho, Er, and Lu that have the formal oxidation state of zero.11 Sm1+ is an attractive target since it could have a half-filled shell 4f7 electron configuration.
Q4. What is the nature of the discovery of new +2 oxidation states?
1–6(1)A natural extension of the discovery of new +2 oxidation states is the pursuit of molecular complexes of lanthanide metals ions in the +1 oxidation state.
Q5. What were the redox potentials for the reduction of 4fn Ln3+?
only Eu, Yb, Sm, Tm, Dy, and Nd were thought to be capable of forming isolable +2 complexes based on the calculated redox potentials for the reduction of 4fn Ln3+ ions to 4fn+1 Ln2+ species.5,6
Q6. How is the coordination geometry of ytterbium in a cryptand?
The coordination geometry of the encapsulated Yb2+ is also irregular, but it can be approximated by a bicapped distorted octahedron with the nitrogen atoms in capping vertices.