Low-Loss and Compact Silicon Rib Waveguide Bends
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Citations
Hybrid plasmonic waveguide-assisted Metal–Insulator–Metal ring resonator for refractive index sensing
Alignment tolerant, low voltage, 0.23 V.cm, push-pull silicon photonic switches based on a vertical pn junction.
Integrated photonics chip with InGaN/GaN light-emitting diode and bended waveguide for visible-light communications
Fluorescent defects and optical structures in metal oxides
Enhancing SiN waveguide optical nonlinearity via hybrid GaS integration
References
Analysis of curved optical waveguides by conformal transformation
Transparent boundary condition for the beam propagation method
Correction to "Analysis of curved optical waveguides by conformal transformation"
The single-mode condition for semiconductor rib waveguides with large cross section
A multi-wavelength 3D-compatible silicon photonics platform on 300mm SOI wafers for 25Gb/s applications
Related Papers (5)
Sharp bends with low losses in dielectric optical waveguides.
Frequently Asked Questions (13)
Q2. What are the conditions used to accurately calculate the leakage and bending losses?
Transparent boundaries conditions are used to accurately calculate the leakage and bending losses introduced by the curvature [6].
Q3. What is the effect of the asymmetry on the rib waveguide?
One can notice that when the bend radius decreases, the exponential variation of the refractive index with r implies a faster reduction for the threshold value r3 than r2, hence inexorably increasing bending losses in dB/unit length, just as what happens in strip waveguide bends.
Q4. What is the effect of asymmetry in a rib waveguide bend?
In the case of a rib waveguide bend, the lateral coupling to the slab is not symmetric: in the inner part of the bend, the refractive index of the slab decreases, while in the outer part of the bend the refractive index of the slab increases.
Q5. What is the bending loss of the silicon waveguide?
The bend losses are approximately constant in the range of wavelength between 1540 to 1580 nm and equal to 0.343±0.154, 0.103±0.044, 0.157±0.0098, and 0.295±0.0021 dB/90° turn at 1.55µm for curvature radii of 20, 30, 50 and 100 µm, respectively.
Q6. What is the way to explain the bending of a rib waveguide?
In conclusion, the authors have demonstrated that an optimal value of the bend radius for rib waveguides, allowing low losses and small footprint, can be obtained for the fundamental quasi-TE mode in a wide range of waveguide widths and heights.
Q7. What is the effect of the asymmetry of the refractive index?
The asymmetry of the refractive index causes the maximum field value of the mode profile to move towards the inner part of the bend (towards the left side, Fig 4a)), therefore reducing the radiation (bending losses) produced by the r3 threshold value.
Q8. What is the effect of the asymmetry on the mode?
the same asymmetry shifts the mode upwards, hence contributing to further decrease losses by reducing the coupling to the slab (leakage losses).
Q9. What is the minimum loss value for a radius of about 25 m?
the minimum loss value (0.09 dB/90ºturn) for a radius of about 25 µm obtained for the target waveguide geometry (70 nm etch and 400 nm waveguide width) is a local minimum among the parameter scan range.
Q10. What is the deviation for a bend radius of 20 m?
The deviation observed for a bend radius of 20 µm was expected and can be explained as follows: the authors have considered in their modeling a perfectly smooth waveguide (i.e. no sidewall roughness) experiencing only the losses produced inherently by the bending and the coupling to the slab mode.
Q11. What is the effect of the asymmetry of the refractive index of the material?
According to their numerical modeling, in the range of curvature between 25 µm and 100 µm, all of the above mentioned effects concur to reduce the total net loss when the curvature is decreased.
Q12. What is the effect of asymmetry in rib waveguides?
in contrast to their strip counterparts, rib waveguide bends exhibit additional internal loss compensation mechanisms.
Q13. What is the accurate way to measure the loss per 90° bend?
In order to extract the loss per 90º bend, a least-square linear regression versus the number of 90° turns is performed wavelength by wavelength using a tunable laser (SANTEC TSL 210-F).